CALCULATIONS FOR THE USP SUGAR BASE
According to USP the Specific Gravity of sugar base is: not less then 1.300
As
D = M / V
M = V * D Where, * = sign of multiplication
D= Specific Gravity, M= Mass, V=Volume,
If
M = V * D
M = X * 1.313
M = X ml.
For Example:
D = 1.313
V = 100 ml
M = x gram So,
M = V * D
M = 100 * 1.313
M = 131.3 grams. So,
131.3 grams is the weight of 100ml USP syrup, Which contains 85 grams of sugar, that means
131.3 – 85 = 46.3 gm water
As
1gm of water is equal to 1ml
so
46.3gm of water is equal to 46.3 ml of water, because the Specific Gravity of water is 1.000
EXAMPLARY CALCULATIONS FOR THE USP SUGAR BASE IN A COUGH SYRUP
If 85gr sugar requires 46.3 ml of water, then how much water is required for 900 kg sugar?
85 : 46.3
900 : X By cross multiplication
X = (46.3 / 85) * 900
X = 490.235 lit.
FACTOR CALCULATION
Water required = 46.3 / 85 * total weight of sugar
Water required = 0.544 * total weight of sugar
So the 0.544 is the factor with the help of which we can easily calculate the water required for USP sugar base.
With any amount of sugar simply multiply 0.544 & the resultant will be the water required for the desired amount of sugar.
Q: In 100 ml USP simple syrup water is 46.3 ml. How much volume sugar will acquire in 100 ml USP simple sugar syrup?
A: As
Volume of sugar in 100 ml syrup = volume of syrup – quantity of water.
= 100 – 46.3
= 53.7ml
Hence, sugar will acquire 53.7 ml volume in 100 ml simple syrup.
Q: If 85 gm sugar acquires 53.7 ml volume. How much volume is acquired by 900kg sugar?
A: As
85 gm sugar : 53.7 ml
900 : X
X = (53.7 / 85) x 900
Vol. of sugar = 568.588 lit.
Hence,
Total volume = Volume of water for 900 kg sugar* + volume of sugar.
Total volume = 489.600 + 568.588
Total volume = 1058.188 liters
*Volume of water for 900 kg sugar = 0.544 x 900
= 489.600 liters.
To know a particular quantity of sugar is present in what volume of Sugar Base:
900 kg Sugar is present in: 1058.188 Liters of Sugar Base
1 kg Sugar is present in: 1058.188/900 = 1.176 Liters
Factor for calculating Volume of Sugar Base in which a particular quantity of sugar is present : 1.176
For Example:
20 kg of sugar will be present in 20 * 1.176 = 23.52 Liters of Sugar Base
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Tuesday, February 24, 2009
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